vector<int> v(22);
bool b = (v[6]);
printf("%d", !b);
- False
- 0
- 1
- This code has an error.
Q2. Which of the following is a reason why using this line is considered a bad practice? (Alternative: Why is using this line considered a bad practice?)
using namespace std;
- The compiled code is always bigger because of all of the imported symbols.
- If the code uses a function defined in two different libraries with the same prototype but possibly with different implementations, there will be a compilation error due to ambiguity.
- It automatically includes all header files in the standard library (cstdint, cstdlib, cstdio, iostream, etc).
- It causes the compiler to enforce the exclusive inclusion of header files belonging to the standard library, generating compilation error when a different header file is included.
typedef struct{
unsigned int age : 4;
unsigned char gender : 1;
unsigned int size : 2;
}child_t;
- 7 bits.
- 25 bytes.
- 1 bit.
- 1 byte.
std::vector<int> v1{1,2,3},v2;
v2=v1;
v1.push_back(4);
v2.push_back(5);
- Error
- v1:{1,2,3,4}; v2:{5};
- v1:{1,2,3,4,5}; v2:{1,2,3,4,5};
- v1:{1,2,3,4}; v2:{1,2,3,5};
- While pointers are variable that hold memory address, iterators are generic functions used to traverse containers. These function allows the programmer to implement read and write code as the container is traversed.
- Incrementing an iterator always means access the next element in the container(if any), no matter the container. Incrementing the pointer means pointing to the next element in memory, not always the next element.
- Pointers are variables that hold memory address where as iterator are unsigned integers that refers to offsets in arrays.
- All iterator are implemented with pointers so all iterators are pointers but not all pointers are iterators.
union {
uint16_t a;
uint32_t b;
int8_t c;
} u1;
- 4 bytes
- 7 bytes
- 8 bytes
- 2 bytes
-
?:
-
new
-
::
-
.
Q8. Which of the following shows the contents of vector pointed by v1 and v2 after running this code?
std:: vector<int> *v1 = new std::vector<int>({1,2,3});
std:: vector<int> *v2;
v2=v1;
v1->push_back(4);
v2->push_back(5);
-
*v1:{1,2,3,4}; *v2:{5};
-
*v1:{1,2,3,4,5}; *v2:{1,2,3,4,5};
- Error
-
*v1:{1,2,3,4}; *v2:{1,2,3,5};
v1 and v2 point to the same vector.
- Because structs are part of the C programming language, there are some complexity between C and C++ structs. This is not the case with classes.
- Classes may have member functions; structs are private.
- The default access specifier for members of struct is public, whereas for member of class, it is private.
- Template type parameters can be declared with classes, but not with the struct keyword.
Templates can be used with both classes and structs Refernce Reference
Q10. Suppose you need to keep a data struct with permission to access some resource based on the days of the week, but you can't use a bool variable for each day. You need to use one bit per day of the week. Which of the following is a correct implementation of a structure with bit fields for this application?
- A
typedef struct {
int sunday:1;
int monday:1;
// more days
int friday:1;
int saturday:1;
} weekdays;
- B
typedef char[7]: weekdays;
- C
typedef struct {
bit sunday:1;
bit monday:1;
// more days
bit friday:1;
bit saturday:1;
} weekdays;
- D
typedef struct {
bit sunday;
bit monday;
// more days
bit friday;
bit saturday;
} weekdays;
Reference NOTE: Correct syntax is that each variable size is 1 bit. bit
is not a type in C++.
- It's a constant expression, meaning an expression composed of constants and operations.
- It's an expression that represents an object with an address.
- It's an expression suitable for the left-hand side operand in a binary operation.
- It's a location value, meaning a memory address suitable for assigning to a pointer or reference.
auto x = 4000.22;
- It specifies that the type of x will be deduced from the initializer - in this case, double.
- It specifies that the type of x is automatic meaning that if can be assigned different types of data throughout the program.
- It specifies that x is a variable with automatic storage duration.
- It specifies that more memory will be allocated for x in case it needs more space, avoiding loss of data due to overflow.
- class written with the generic programming paradigm, specifying behavior in terms of type parameter rather than specific type.
- blank superclass intended for inheritance and polymorphism.
- class that only consists of member variable, with no constructor, destructor nor member functions.
- skeleton source code for a class where the programmer has to fill in specific parts to define the data types and algorithms used.
if(x)
y=a;
else
y=b;
-
y=a?b:x;
-
y=if(x?a:b);
-
y=(x&a)?a:(x&b)?b:0;
-
y=x?a:b;
#include <iostream>
int main(){
int x=10, y=20;
std::cout << "x = " << x++ << " and y = " << --y << std::endl;
std::cout << "x = " << x-- << " and y = " << ++y << std::endl;
return(0);
}
-
x = 10 and y = 20
x = 11 and y = 19
-
x = 11 and y = 19
x = 10 and y = 20
-
x = 10 and y = 19
x = 11 and y = 20
-
x = 11 and y = 20
x = 10 and y = 19
Q16. What is the meaning of the two parts specified between parentheses in a range-based for loop, separated by a colon?
- The first is a variable declaration that will hold an element in a sequence. The second is the sequence to traverse.
- The first is an iterator, and the second is the increment value to be added to the iterator.
- The first is the iterating variable. The second is an
std::pair
that specifies the range (start and end) in which the variable will iterate. - The first is a container object. The second is an
std::pair
that specifies the range (start and end) in which the elements will be accessed within the loop.
int8_t a=200;
uint8_t b=100;
if(a>b)
std::cout<<"greater";
else
std::cout<<"less";
- There is no output because there is an exception when comparing an int8_t with a uint8_t.
- greater
- less
- There is no output because there is a compiler error.
Note: a variant of the question below.
int8_t a=200;
uint8_t b=100;
std::cout<<"a="<<(int)a;
std::cout<<", b="<<(int)b;
- a=-56, b=100
- a=-55, b=100
- a=200, b=-156
- a=200, b=100
Note: Implicit conversion from 'int' to 'int8_t' (aka 'signed char') changes value from 200 to -56
int x=5, y=2;
if(x & y) {
/*_part A_*/
}
else {
/*_part B_*/
}
- Part A executes because x==5 (true) and y==2 (true), thus the AND operation evaluates as true.
- Part B executes because (x & y) results in 0, or false.
- Part A executes because (x & y) results in a nonzero value, or true.
- Part B executes because the statement (x & y) is invalid, thus false.
Q20. What is a valid definition for the get_length
function, which returns the length of a null-terminated string?
- A
int get_length(char *str) {
int count=0;
while(str[count++]);
return count-1;
}
- B
int get_length(char *str) {
int count=0;
while(str!=NULL){
count++;
str++;
}
return count;
}
- C
int get_length(char *str) {
int count=0;
while((*str)++)
count++;
return count;
}
- D
int get_length(char *str) {
int count=0;
while(str++)
count++;
return count;
}
Q21. Which STL class is the best fit for implementing a collection of data that is always ordered so that the pop operation always gets the greatest of the elements? Suppose you are interested only in push and pop operations.
-
std::list
-
std::vector
-
std::priority_queue
-
std::map
Q22. What is the meaning of the three sections specified between parentheses in a for loop separated by semicolons?
- The first is the iterating variable name, the second is the number of times to iterate, and the third is the desired increment or decrement (specified with a signed integer).
- The first is the initialization block, the second is the condition to iterate, and the third is the increment block.
- The first is the iterating variable, the second is the container in which it should operate, and the third is an exit condition to abort at any time.
- The first is the iterating variable name, the second is the starting value for the iterating variable, and the third is the stop value (the last value plus one).
int i = 0;
printf("%d", i++);
printf("%d", i--);
printf("%d", ++i);
printf("%d", --i);
- 0,1,1,0
- 0,1,0,1
- 0,0,1,0
- 1,0,1,0
void *ptr;
- It is a pointer initialized at NULL.
- It is a pointer to a void function.
- That declaration causes a compiler error, as pointers must specify a type.
- It is a pointer to a value with no specific type, so it may be cast to point to any type.
int c=3; char d='A';
std::printf("c is %d and d is %c",c,d);
- c is d and d is c
- c is A and d is 3
- c is 3 and d is A
- c is c and d is d
printf("1/2 = %f",(float)(1/2));
- 1/2 = 0.499999
- 1/2 = 0
- 1/2 = 0.000000
- 1/2 = 0.5
- Public members are the same as global variables, so every part of the code has access to them. Private members are the same as automatic variables, so only their class has access to them.
- Public members are made accessible to any running application. Private members are made accessible only to the application where the object is instantiated.
- Public members will be compiled as shared variables in a multithreaded environment. Private members will be compiled as Thread-local variables.
- Public members can be accessed by any function. Private members can be accessed only by the same class's member functions and the friends of the class.
int x=10, a=-3;
x=+a;
- 3
- 7
- -3
- 13
- Only classes can have member variables and methods.
- C++ supports multiple inheritance.
- C++ supports only single inheritance.
- Only structs can inherit.
Q30. Consider a pointer to void, named ptr
, which has been set to point to a floating point variable g
. Which choice is a valid way to dereference ptr
to assign its pointed value to a float variable f
later in the program?
float g;
void *ptr=&g;
-
float f=*(float)ptr;
-
float f=(float *)ptr;
-
float f=(float)*ptr;
-
float f=*(float *)ptr;
- It is the same as the class member access operator, or arrow operator
(->)
, which allows you to access a member of an object through a pointer to the object. - It is the pointer to member operator, and it allows you to access a member of an object through a pointer to that specific class member.
- It is the member access with address of operator, which returns the address of a class or struct member.
- It is a combination of the member access operator
(.)
and the dereference operator(*)
, so it allows you to access the object that a member pointer points to.
Q32. For these declarations, which choice shows four equivalent ways to assign the character "y" in the string to a char variable c?
char buff[50] = "strings as arrays of characters are fun!"
char *str = buff+11;
char c;
- A
c = buff[16];
c = str[5];
c = *(buff+16);
c = *(str+5);
- B
c = *(buff[15]);
c = *(str[4]);
c = buff+15;
c = str+4;
- C
c = buff[15];
c = str[4];
c = *(buff+15);
c = *(str+4);
- D
c = *(buff[16]);
c = *(str[5]);
c = buff+16;
c = str+5;
Q33. Which choice is the correct declaration for the class named Dog, derived from the Animal class?
class Animal{
//....
}
- A
class Dog :: public Animal {
//....
};
- B
class Dog : public Animal {
//....
};
- C
public class Animal :: Dog {
//....
};
- D
public class Dog extends Animal {
//....
};
#include <cstdio>
using namespace std;
int main(){
char c = 255;
if(c>10)
printf("c = %i, which is greater than 10", c);
else
printf("c = %i, which is less than 10", c);
return 0;
}
- c = -1, which is less than 10
- c = 255, which is greater than 10
- c = -1, which is greater than 10
- c = 255, which is less than 10
Technically, whether a char
is signed
or unsigned
is implementation-defined;
in the latter case, the second answer would be correct.
Reference
- by simply calling the C code
- there is no way for C++ to call a C function
- by using extern "C"
- by importing the source C code
Q36. Which choice is not a valid type definition of a structure that contains x and y coordinates as integers, and that can be used exactly as shown for the variable named center
?
coord center;
center.x = 5;
center.y = 3;
- A
typedef struct coord {
int x;
int y;
};
- B
typedef struct coord {
int x;
int y;
} coord;
- C
typedef struct {
int x;
int y;
} coord;
- D
struct coord {
int x;
int y;
};
typedef struct coord coord;
Q37. Which choice does not produce the same output as this code snippet? Assume the variable i
will not be used anywhere else in the code.
for (i=1;i<10;i++){
cout<<i<<endl;
}
- A
i=1;
while(i<10){
cout<<++i<<endl;
}
- B
for (int i:{1,2,3,4,5,6,7,8,9}) {
cout<<i<<endl;
}
- C
i = 1;
do {
cout<<i++<<endl;
} while(i<10);
- D
i = 1;
loop:
cout<<i++<<endl;
if(i<10) goto loop;
#include "library.h"
- It causes the toolchain to compile all the contents of library.h so that its executable code is available when needed by the final application.
- It cherry picks library.h for the declarations and definitions of all data and functions used in the remainder of the source file main.cpp, finally replacing the
#include
directive by those declarations and definitions. - It informs the linker that some functions or data used in the source file main.cpp are contained in library.h, so that they can be called in run time. This is also known as dynamic linking.
- It causes the replacement of the
#include
directive by the entire contents of the source file library.h. This is similar to a Copy-Paste operation of library.h into main.cpp.
Q39. Consider this function declaration of is_even
, which takes in an integer and returns true if the argument is an even number and false otherwise. Which declarations are correct for overloaded versions of that function to support floating point numbers and string representations of numbers?
bool is_even(int);
- A
bool is_even(float f);
bool is_even(char *str);
- B
bool is_even(float f);
bool is_even(char str);
- C
bool is_even_float(float f);
bool is_even_str(char *str);
- D
float is_even(float f);
char *is_even(char *str);
- A
#ifdef MY_LIBRARY_H
#define MY_LIBRARY_H
// my_library.h content
#endif /* MY_LIBRARY_H */
- B
#ifndef MY_LIBRARY_H
#define MY_LIBRARY_H
// my_library.h content
#endif /* MY_LIBRARY_H */
- C
#ifdef MY_LIBRARY_H
#undef MY_LIBRARY_H
// my_library.h content
#endif /* MY_LIBRARY_H */
- D
#define MY_LIBRARY_H
#include MY_LIBRARY_H
// my_library.h content
#undef MY_LIBRARY_H
std::vector<std::vector<int>> thematrix;
- There's nothing wrong with it.
- An
std::vector
cannot contain morestd::vector
containers as its elements. - The correct syntax should be:
std::vector[std::vector[int]] thematrix;
-
>>
is parsed as the shift-right operator, and thus results in a compile error.
sprite->x
-
sprite.x
-
sprite.*x
-
(*sprite).x
-
*sprite.x
complexNumber(float real, float im)
: real_part(real),
im_part(im){}
- A
complexNumber(float real, float im) {
this->real = real_part;
this->im = im_part;
}
- B
complexNumber(float real, float im) {
this->real_part(real);
this->im_part(im);
}
- C
complexNumber(float real, float im) {
this->real_part = real;
this->im_part = im;
}
- D
complexNumber(float real, float im) {
this->real_part = ℜ
this->im_part = &im;
}
bool x=true, y=false;
if (~x || y) {
/*part A*/
} else {
/*part B*/
}
- Part A executes because the expression
(~x || y)
always results in true ify==false
. - Part B executes because the statement
(~x || y)
is invalid, thus false. - Part A executes because
~x
is not zero, meaning true. - Part B executes because
~x
is false andy
is false, thus theOR
operation evaluates as false.
int32_t nums[3]={2,4,3};
std::cout << ( nums[0] << nums[1] << nums[2] );
- The output is the addresses of
nums[0]
,nums[1]
, andnums[2]
, in that order, with no spaces. - 256
-
0
-
243
float values[5]={0.54f, 2.71828f, 3.14159f, 5.499999f, 10.0f};
for(auto f:values)
printf("%i ",(int)(f+0.5f));
-
0.54 2.71828 3.14159 5.499999 10.0
-
1 3 4 6 11
-
0 2 3 5 10
-
1 3 3 5 10
Q47. Which of the following STL classes is the best fit for implementing a phonebook? Suppose each entry contains a name and a phone number, with no duplicates, and you want to have lookup by name.
-
std::priority_queue
-
std::list
-
std::vector
-
std::map
#include <iostream>
#include <fstream>
using namespace std;
int main(){
ifstream file1("text1.txt", ios::binary);
ofstream file2("text2.txt", ios::binary);
file2 << file1.rdbuf();
}
- It renames text1.txt to text2.txt.
- It makes a directory called text2.txt and moves text1.txt there.
- It copies the contents of text1.txt into text2.txt - i.e., it makes a copy of text1.txt, named text2.txt.
- It appends the contents of text1.txt into text2.txt - i.e., replaces the contents of text2.txt by the concatenation of text2.txt and text1.txt.
Q49. Which of the following is not a consequence of declaring the member variable count
of my_class as static? / Alt.: Which statement is true when declaring the member variable count
as static?
class my_class {
public: static int count;
}
- The variable cannot be modified by any part of the code in the same application or thread. However, other threads may modify it.
- The variable exists even when no objects of the class have been defined so it can be modified at any point in the source code.
- The variable is allocated only once, regardless of how many objects are instantiated because it is bound to the class itself, not its instances.
- All objects that try to access their count member variable actually refer to the only class-bound static count variable.
- double
- long float
- long double
- float
my_class *my_object = new my_class();
-
delete(my_object);
-
free(my_object);
- The garbage collector will destroy the object eventually.
- Exiting the scope will destroy the object.
Q52. What is the correct way to call the count
member function for the object pointer called grades
?
class my_array{
public:
int count();
}; // ... more members above
int main(){
my_array *grades = new my_array();
}; // ... more code above
-
grades.count();
-
my_array->count();
-
grades->count();
-
my_array.count();
int i0=4, i1=6, i2=8;
int& nums[3]={i2,i0,i1};
std::cout<<nums[0]<<nums[1]<<nums[2];
- There is no output. The code causes a compiler error because
nums
is an array of references, which is illegal. - 846
- The output is the addresses of
i2
,i0
, andi1
, in that order, with no spaces. - 468
typedef struct{
unsigned int age : 4;
unsigned char gender : 1;
char : 0;
unsigned int size : 2;
}child_t;
- Yes, it causes a compiler error because the colon character is not allowed in struct definitions.
- No, and
child_t
is a type defined as a structure with bit fields. It has 4 bits for age and 1 bit for gender in the first byte, and 2 bits for size in the second byte. - Yes, it causes a compiler error because there is an unnamed field.
- Yes, it causes a compiler error because one field is defined as having a size of 0.
A->B
-
*(A.B)
-
B=A
-
(*A).B
-
&A.B
Note: a simpler variant of the question below.
A->B->C->D
-
A.B.C.D
-
*A.*B.*C.*D
-
&A.&B.&C.&D
-
*(*((*A).B).C).D
Note: a more complex variant of the question above.
auto buff = new char[50];
std::memset(buff,20,50);
- It declares a memory buffer named buff that starts at address 20 and ends at address 70.
- It sets all bits in the array named buffer from its element at index 20 to its element at index 50.
- It writes the value 20 in every memory address from buff to buff+49.
- It declares a memory buffer named buff that starts at address 20 and ends at address 50.
Q58. Consider a class named CustomData
. Which choice is a correct declaration syntax to overload the postfix ++
operator as a class member?
-
CustomData& operator++();
-
void operator++(CustomData);
-
CustomData operator++(CustomData);
-
CustomData operator++(int);
Q59. You want to sort my_array, declared below. Which choice is the correct call to std::sort, using a lambda expression as the comparison function?
std::array<uint32_t, 50> my_array;
- A
std::sort(my_array.begin(), my_array.end(),
[](uint32_t a, uint32_t b) {
return a < b;
})
- B
lambda(uint32_t a, uint32_t b){
return a < b;
}
std::sort(my_array.begin(), my_array.end(), lambda);
- C
std::sort(my_array.begin(), my_array.end(),
lambda(uint32_t a, uint32_t b){
return a < b;
})
- D
lambda(uint32_t a, uint32_t b){
return a < b;
}
std::sort(my_array.begin(), my_array.end(), &lambda);
Q60. Which choice is the most reasonable implementation of the function std::mutex::lock() by using std::mutex::try_lock()?
- A
void std::mutex::lock(){
while(!this->try_lock());
}
- B
void std::mutex::lock(){
return (this->try_lock());
}
- C
void std::mutex::lock(){
while(1)
this->try_lock();
}
- D
void std::mutex::lock(){
while(this->try_lock());
}
Note: variant of the question below.
std::mutex::lock()
std::mutex::try_lock()
-
lock()
has a higher privilege overtry_lock()
. This means that you have a better chance of acquiring a mutexwith lock()
. - Both attempt to acquire a lock, but
lock()
blocks if the mutex is not available, whereastry_lock()
returns whether the mutex is available or not. -
lock()
enforces preemption, whereastry_lock()
suggests preemption. - If the mutex is not available,
try_lock()
returns with a corresponding code, whereaslock()
snatches the mutex from the thread that currently has it.
Note: variant of the question above.
- It allows the programmer to write the necessary code to free the resources acquired by the object prior to deleting the object itself.
- It deletes an object. One example of a destructor is the
delete()
function. - It terminates a program. This may be achieved as a regular function call or as an exception.
- There are no destructors in C++.
Q63. What is one benefit of declaring the parameter as a const
reference instead of declaring it as a regular object?
int calculateMedian(const my_array& a)
- Actually, objects cannot be passed as regular variables, because they require a constructor call. Therefore, a
const
reference is the only way to pass class instances to functions. - There are no benefits because a reference and an object are treated as the same thing.
- The
const
qualifier forbids the code to modify the argument, so the programmer can rest assured that the source object will remain unchanged. / Alt.: The argument is passed as a reference, so if the passed my_array object is large, the program will require less time and memory. - The argument is passed as a reference, so the Function receives a copy that can be modified without affecting the original variable.
- a preprocessor directive that prevents inconsistent behaviors in lines that contain the #ifdef, #ifndef, or #elif directives
- a compiler option that prevents the user code from including additional libraries
- a preprocessor statement that prevents a source file from being included more than once in a project
- a library that adds safety features such as mutexes, watchdog timers, and assertions to the project
- A
public: Sprite();
- B
private: void Sprite();
- C
public: void Sprite();
- D
private: Sprite();
#pragma once
- to restrict the use of its contents to only one source file
- to tell the compiler that only one variable can be instantiated from the classes or types contained in this header file
- to help the compiler finish faster by assuring that only one compiler pass is neccessary for the code included in this header file
- to make the compiler parse that header file only once, even if it is included multiple times in the source
- a 2-tuple
- an integer number
- a floating point number
- a string with more than 255 characters
- shifting characters to the left in a string.
- inserting characters into an output stream like std::cout.
- comparing floating point numbers as less-than.
- assigning a variable to a reference.
Q69. Which choice is a reason to specify the type of a pointer instead of using void *
, which works as a pointer to any type?
- The compiler needs the data type to make sure that the pointer is not going to be used on illegal non-pointable types such as functions, labels, pointers, and reference.
-
void *
does not work for any type. The language does not allow assigning anything other thanvoid
to a pointer tovoid *
. - The compiler needs the data type to know how much memory to allocate for the pointer, because different data types require different pointer lengths.
- Yes, it causes a compiler error because one field is defined as having a size of 0.
#include <iostream>
char str[20];
int main(){
std::cout << "What's your name? ";
str << std::cin
std::cout << "Hello, " << str;
return 0;
}
- The main function is supposed to have a void return type.
-
std::cin
andstd::cout
are invalid. The correct names for the character input and output streams arecin
andcout
. - The address of
str
is supposed to be used. That is&str
instead ofstr
. - The input operator flow is inverted. it should start from
std::cin
and then flow (>>) intostr
.
Q71. When placed in a valid execution context, which statement will dynamically allocate memory from the heap for an integer of value 11?
-
int anInt = new int(11);
-
int* anInt = new int[11];
-
int anInt = new int[11];
-
int* anInt = new int(11);
- an integer number of at least 32 bits
- a string with more than 255 characters
- a pointer
- a 64-bit floating point number
-
struct
-
union
-
enum
-
namespace
-
marks["Sinead"] = 22
-
marks["Sinead"].22
-
marks["Sinead"] -> 22
-
marks["Sinead"].value = 22
-
The std::sort function is a template. The programmer is free to enter the sorting algorithm in a function object as an argument.
-
Actually, std::sort takes only one argument, which is the container to be sorted.
-
std::sort operates on a template container. The compiler does not know how to relationally compare the values it contains, so a function must be provided to do the comparison.
-
std::sort will use the parameter function as an error handler. The function will be called if an error occurs.
#include <iostream>
int main() {
float a = 5.51;
int b = static_cast<int>(a);
std::cout << b;
}
-
6 will be printed on standard output, with no compilation warnings generated.
-
5 will be printed on standard output, with no compilation warnings generated.
-
6 will be printed on standard output, with compilation warnings generated.
-
5 will be printed on standard output, with compilation warnings generated.
Q77. Which access specifier does not allow class members to be accessed from outside the class, but allows them to be accessed by derived classes?
- guarded
- protected
- public
- private
- a.exe
- a
- a.out
- out.a
#include <iostream>
using namespace std;
int main() {
int a=1;
cout<<(a++)*(++a)<<endl;
return 0;
}
- 1
- 2
- 3
- 6
- compiler
- console
- character
- standard namespace
- Current Input Pointer position
- Current Output Pointer position
- Last Input Pointer position
- Last Output Pointer position
- Pointer for a pointer
- Pointer for a function
- function for a pointer
- function for a class
- cout << "Hello World";
- System.out.println("Hello World");
- print("Hello World");
- Console.WriteLine("Hello World");
- 4
- 3
- 7
- 5
- It inherit other class
- It has a pointer variable
- It is the first class declared
- Another class got inherit from this class
Q86. Size of C++ objects are expressed in terms of multiples of the size of a ** and the size of a char is **.
- char, 4
- float, 8
- int, 1
- char, 1
-
<numeric>
-
<limit>
-
<limits>
-
<implementation>
- a constructor that can be used with no arguments
- a contructor that does not have a return value
- a constructor that is used by multiple classes
- a constructor that initializes all members of a class
- There is no reason to choose because they serve different purposes
- An include guard uses a macro to achieve single inclusion, but the compiler cannot prevent the programmer from defining that macro elsewhere, which would result in no inclusion at all defining that macro elsewhere, which would result in no inclusion at all
- '#pragma once' guarantees that the header code will never be changed because it is enforced by the compiler
- Include guards refer to the header file in the file system, not to the code, so they are not helpful if the header file exists more than once in a project. This is not a problem with '#pragma once'
- We can create new c++ operator.
- We can change the precedence of the c++ operator.
- We can not change the operator templates.
- We can change the associativity of the c++ operators.
- Copy Constructor
- Assignment Operator
- A constructor without any parameter
- All of the above
- certain structure
- choosing structure
- selective structure
- None of the Above
- [ ]
void fact(int n) {
if (n <= 0)
return 0;
else
return 1;
}
- [ ]
int fact(int n) {
if (n <= 0)
return 1;
else
return (fact(n) * (n-1));
}
- [ ]
int fact(int n) {
if (n >= 0)
return 1;
else
return (fact(n-1) * n);
}
- [x]
int fact(int n) {
if (n <= 0)
return 1;
else
return (fact(n-1) * n);
}
Q94. A class destructor can be called when a variety of situations occur. Which choice is not one of those situations?
- The program is terminated. This calls the destructor of static duration objects.
- The delete () function is called for an object pointer assigned with the new operator.
- The garbage collector detects that an object is no longer going to be used.
- An automatic storage duration object goes out of scope.
Q95. You are designing a foreign exchange payments system in C++, You need to model a transaction of a currency that has an integer as its quantity and a float as its price. You then want to declare an actual object of this type. How will vou achieve this?
- A
struct currencyDeal {
float price;
int quantity;
};
currencyDeal firstDeal;
- B
union currencyDeal {
float price;
int quantity;
};
currencyDeal firstDeal;
- C
struct currencyDeal {
float price;
int quantity;
};
- D
union currencyDeal {
float price;
int quantity;
};
int checkConcatThreshold(string a, string b) {
return (a + b).length () > 120;
}
- A compilation warning will occur and the second argument will be given a default value of b.
- A compilation warning will occur and the second argument will be given a default value of empty string.
- A compilation error will occur.
- No compilation errors will occur and no compilation warnings will occur.
Q97. You need to define a C++ lambda function. You want the function to have access to only the variables that are local to it. The function should receive a single parameter, a name, and construct a simple greeting. How will you achieve this?
- A
auto myVeryFirstLambda = [=] (string name) {
return "Hello " + name + "!";
};
- B
myVeryFirstLambda = [&] (string name) {
return "Hello " + name + "!";
};
- C
auto myVeryFirstLambda = [] (string name) {
return "Hello " + name + "!";
};
- D
myVeryFirstLambda = [] (string name) {
return "Hello " + name + "!";
};
int x=10, a=-3;
X+=a;
- -3
- 7
- 13
- 3
Explanation : +=
means increasing value. So x += a
is equivalent to x = x + a