937. Reorder Data in Log Files[Easy].md

• problem

  You are given an array of logs. Each log is a space-delimited string of words, where the first word is the identifier.
  
  There are two types of logs:
  
  Letter-logs: All words (except the identifier) consist of lowercase English letters.
  Digit-logs: All words (except the identifier) consist of digits.
  Reorder these logs so that:
  
  The letter-logs come before all digit-logs.
  The letter-logs are sorted lexicographically by their contents. If their contents are the same, then sort them lexicographically by their identifiers.
  The digit-logs maintain their relative ordering.
  Return the final order of the logs.
  
   
  
  Example 1:
  
  Input: logs = ["dig1 8 1 5 1","let1 art can","dig2 3 6","let2 own kit dig","let3 art zero"]
  Output: ["let1 art can","let3 art zero","let2 own kit dig","dig1 8 1 5 1","dig2 3 6"]
  Explanation:
  The letter-log contents are all different, so their ordering is "art can", "art zero", "own kit dig".
  The digit-logs have a relative order of "dig1 8 1 5 1", "dig2 3 6".
  Example 2:
  
  Input: logs = ["a1 9 2 3 1","g1 act car","zo4 4 7","ab1 off key dog","a8 act zoo"]
  Output: ["g1 act car","a8 act zoo","ab1 off key dog","a1 9 2 3 1","zo4 4 7"]
   
  
  Constraints:
  
  1 <= logs.length <= 100
  3 <= logs[i].length <= 100
  All the tokens of logs[i] are separated by a single space.
  logs[i] is guaranteed to have an identifier and at least one word after the identifier.

• solve

  class Solution:
      def reorderLogFiles(self, logs: List[str]) -> List[str]:
          log = []
          for l in logs:
              if l[-1].isnumeric():
                  log.append(l)
              else:
                  for i, l2 in enumerate(log):
                      if l2[-1].isalpha():
                          tmp1 = l.split()
                          tmp2 = l2.split()
                          if tmp1[1:] < tmp2[1:]:
                              log.insert(i, l)
                              break
                          elif tmp1[1:] == tmp2[1:]:
                              if tmp1[0] < tmp2[0]:
                                  log.insert(i, l)
                                  break
                      else:
                          log.insert(i, l)
                          break
                  else:
                      log.append(l)
          return log