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Geometry Processing – Alignment and Registration

Edges & Euler Characteristic

HW00

Wikipedia progress?

Geometry processing: Revision history

Geometry processing category

Quadratic energies and linear systems

HW01

An Introduction to the Conjugate Gradient Method Without the Agonizing Pain, Shewchuk 1994.

Registering Multiple Scans

source

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Matching surfaces that share a parameterization

For example, consider if a surface $X$ is given with a parameterization so that each point on $X$ can be written as a function of parameters $u$ and $v$, $\x(u,v) ∈ X$. If $Y$ is another surface produced by the same parameterization ($\y(u,v) ∈ Y$), then we can think of $Y$ as a deformation of $X$ (or vice-versa). Each point $\y(u,v)$ on the surface $Y$ has a natural corresponding point $\x(u,v)$ on $X$ via the parameters $u$ and $v$.

The surface of a Beetle is deformed into a new surface. The parameterization of the original surface allows us to identify the corresponding points on the deformed surface. image source

A very natural way to measure the difference between these two surfaces aggregate the distance between each pair of corresponding points. For example, we could integrate this distance over the parametric domain (w.l.o.g. let's say valid values are $u,v ∈ (0,1)$):

\[ D_2(X,Y) = \sqrt{ ∫_0^1∫_0^1 ‖\x(u,v) - \y(u,v)‖² ;du;dv } \]

This measure will be zero if the surfaces are the same for any choice of parameters $u$ and $v$. The measure $D_2(X,Y)$ could large if every point on $Y$ is slightly deformed or if a few bad points are deformed a lot. This distance is the L² norm of the magnitude of the displacement from $X$ to $Y$ (or vice-versa):

\[ D_2(X,Y) = \sqrt{ ∫_0^1∫_0^1 d(u,v)² ;du;dv }, \quad \text{ and } \quad d(u,v) = ‖\x(u,v) - \y(u,v)‖ \]

We can directly measure the maximum distance between corresponding points, the $L^∞$ norm:

\[ D_∞(X,Y) = \lim_{p→∞} \sqrt[p]{∫_0^1∫_0^1 d(u,v)^p ;du;dv } = \sup\limits_{u,v ∈ (0,1)} ‖\x(u,v) - \y(u,v)‖, \]

where $\sup$ takes the supremum (roughly the continuous math analog of the maximum).

The measure $D_∞$ will also be exactly zero if the surfaces are the same.

Triangle meshes

On the computer, we can store an explicit surface as a triangle mesh. Triangle meshes have an implicit parameterization: each triangle can be trivially and independently mapped to the unit triangle, via its barycentric coordinates.

Triangle meshes also afford an immediate analog of deformation: moving each vertex of the mesh (without change the mesh combinatorics/topology).

So if $\V_X ∈ \R^{n × 3}$ represents the vertices of our surface $X$ with a set $F$ of $m$ triangular faces and $\V_Y ∈ \R^{n × 3}$ the vertices of deformed surface $Y$, then we can rewrite our measure $D_2$ above as a sum of integrals over each triangle:

\[ ∑\limits_{{i,j,k} ∈ T} \sqrt{ ∫_0^{1-u} ∫_0^1 \left| \underbrace{\left(u \v_x^i + v \v_x^j + (1-u-v) \v_x^k\right)}_\x

\underbrace{\left(u \v_y^i + v \v_y^j + (1-u-v) \v_y^k\right)}_\y \right|^2 ;du;dv } \]

Note: The areas of the triangles in our mesh may be different. So this measure may be thrown off by a very large triangle with a small difference and may fail to measure a very small triangle with a large difference. We'll learn how to account for this, later.

Unfortunately, in many scenarios we do not have two co-parameterized surface or a simple per-vertex mesh deformation. Instead, we may have two arbitrary surfaces discretized with different meshes of different topologies. We will need a measure of difference or distance between two surfaces that does not assume a shared parameterization.

(undirected) Hausdorff distance

To form a metric in the mathematical sense, a distance measure should be symmetric: distance from $X$ to $Y$ equals distance from $Y$ to $X$. Hausdorff distance is defined as the maximum of directed Haurdorff distances:

\[ D_{H}(X,Y) = \max \left[ D_{\overrightarrow{H}}(X,Y)\ , \ D_{\overrightarrow{H}}(Y,X) \right]. \]

Unlike each individual directed distance, the (undirected) Hausdorff distance will measure zero if and only if the point set of the surface $X$ is identical to that of $Y$.

Hausdorff distance between triangle meshes

On the computer, surfaces represented with triangle meshes (like any point set) admit a well-defined Hausdorff distance between one-another. Unfortunately, computing exact Hausdorff distance between two triangle meshes remains a difficult task: existing exact algorithms are prohibitively inefficient.

We do not know a priori which point(s) of each triangle mesh will end up determining the maximum value. It is tempting, optimistic, but ultimately incorrect to assume that the generator points will be one of the vertices of the triangle mesh. Consider if a triangle $t$ connected corners at $(1,1,0)$, $(1,0,1)$ and $(0,1,1)$ and $B$ was a mesh with two triangles, the first connecting $(0,0,0)$, $(1,0,1)$ and $(1,1,0)$ and the second connecting $(0,0,0)$, $(0,1,1)$ and $(1,1,0)$. The corners of $t$ also appear as vertices of $B$, so clearly their respective vertex-to-mesh distances are zero, yet the maximum minimum distance from $t$ to $B$ is clearly non-zero (it is $\sqrt{3}/3$).

The directed Hausdorff distance from the orange triangle $A$ to the blue, two-triangle mesh $B$ is non-zero (generated by red segment), but the distance from each corner of $A$ to $B$ is zero.

One might also optimistically, but erroneously hope that by considering the symmetric Hausdorff distance one of the generator points must lie on a vertex of $A$ or of $B$. Unfortunately, this only follows for convex shapes.

The directed Hausdorff distance to the blue "alligator" shape in 2D from its orange convex hull is generated by non-vertex points. Since the symmetric Hausdorff distance is the maximum of this and the smaller distance from the blue shape to the orange shape, it is also generated by these non-vertex points.

Integrated closest-point distance

Symmetric matching distance

We can similarly define a symmetric distance by summing the two directed distances:

\[ D_{C}(X,Y) = D_{\overrightarrow{C}}(X,Y) + D_{\overrightarrow{C}}(Y,X) = \sqrt{\ ∫\limits_{\x∈X} ‖\x - P_Y(\x) ‖² ;dA }+ \sqrt{\ ∫\limits_{\y∈Y} ‖\y - P_X(\y) ‖² ;dA }. \]

Unconstrained ICP

If we place no restrictions or constraints on the transformation $T: \R³ → \R³$, then there are many trivial solutions to minimizing $E_{\overrightarrow{C}}(T(X),Y)$. For example, we could simply define $T$ so that every point $\x$ gets mapped to its closest point on $Y$: $T(\x) := P_Y(\x)$. This would clearly induce $E_{\overrightarrow{C}}=0$. Actually, we could get zero energy even if we define $T$ to map all points on $X$ to the same arbitrary point on $Y$: $T(\x) := \y$.

Symmetric energy for complete matches

If $X$ and $Y$ are complete matches, then one way to remove these trivial solutions is to minimize the symmetric energy summing energies from $X$ to $Y$ and from $Y$ to $X$:

\[ E_C(T(X),Y) = E_{\overrightarrow{C}}(T(X),Y) + E_{\overrightarrow{C}}(Y,T(X)). \]

Appending the energy $E_{\overrightarrow{C}}(Y,T(X))$ measure the distance from all points on $Y$ to the transformed surface $T(X)$ ensures that we will not get zero energy if some part of $Y$ does not get matched to some part of $X$.


Sofien Bouaziz's PhD Thesis

Sections 3.2-3.3 provide a modern optimization-view of iterative closest point method. Places ICP as an instance of a very powerful "space of optimization techniques". New way of looking at just about any optimization problem.

Source

Point-to-plane vs. point-to-plane

ICP using the point-to-point matching energy linearization is slow to converge.

ICP using the point-to-plane matching energy linearization is faster.