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24_remove-nth-node-from-end-of-list.cpp
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24_remove-nth-node-from-end-of-list.cpp
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// DATE: 02-Aug-2023
/* PROGRAM: 24_Linked List - Remove Nth Node From End of List
https://leetcode.com/problems/remove-nth-node-from-end-of-list/
Given the head of a linked list, remove the nth node from the end of the list and return its head.
Example 1:
Input: head = [1,2,3,4,5], n = 2
Output: [1,2,3,5]
Example 2:
Input: head = [1], n = 1
Output: []
Example 3:
Input: head = [1,2], n = 1
Output: [1]
*/
// @ankitsamaddar @Aug_2023
#include <iostream>
#include <vector>
using namespace std;
struct ListNode {
int val;
ListNode *next;
ListNode() : val(0), next(nullptr) {}
ListNode(int x) : val(x), next(nullptr) {}
ListNode(int x, ListNode *next) : val(x), next(next) {}
};
class Solution {
public:
ListNode *removeNthFromEnd(ListNode *head, int n) {
ListNode *res = new ListNode(0, head);
ListNode *left = res;
ListNode *right = head;
while (n > 0 and right) {
right = right->next;
n--;
}
while (right) {
left = left->next;
right = right->next;
}
left->next = left->next->next;
return res->next;
}
};
void printList(ListNode *head) {
while (head != NULL) {
cout << head->val << " ";
head = head->next;
}
cout << endl;
}
int main() {
ListNode *list1 = new ListNode(1);
list1->next = new ListNode(2);
list1->next->next = new ListNode(3);
list1->next->next->next = new ListNode(4);
list1->next->next->next->next = new ListNode(5);
printList(list1);
int n = 2;
Solution sol;
ListNode *result = sol.removeNthFromEnd(list1, n);
printList(result);
return 0;
}