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b) I would not expect a better result as randomly generated numbers will appear at approximately equal rates.
####17)
Based on 50000 attempts, I won 5035 games - 10.07% of the games.
####21)
If the player fails the first shot at a 28% chance, he receives 0 points. ($0 \cdot 0.28$)
If the first shot succeeds and the second one fails, he receives 1 point. ($1 \cdot 0.72 \cdot 0.28$)
If both shot succeed, he receives two points. ($2 \cdot 0.72^2$)
The sum of these values is $0 \cdot 0.28 + 1 \cdot 0.72 \cdot 0.28 + 2 \cdot 0.72^2 = 1.2384$. Rounding to an integral value, he will score one point on average.