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prim.c
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prim.c
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/**
* file: prim.c
* author: yusuf shakeel
* date: 2014-03-02
*
* description: find MST using prim's algorithm
*
* vertices are represented using numbers.
* vertex A becomes 0
* vertex B becomes 1
* and so on...
*/
#include <stdio.h>
#include <stdlib.h>
/**
* contant to represent infinity
* it is assumed that edges of the graph will have weight less than this value
*/
#define INF 9999
/**
* total number of vertices in the graph
*/
#define V 4
/**
* this function will display the MST
*/
void displayMST(int graph[V][V], int markedCell[V][V]) {
int r, c;
for (r = 0; r < V-1; r++) {
for (c = r+1; c < V; c++) {
if(markedCell[r][c]) {
printf("Edge: %d -- %d\tWeight: %d\n", r, c, graph[r][c]);
}
}
}
}
/**
* prim&aposs algorithm function
*/
void prim(int graph[V][V]) {
//variables
int i, r, c,
solved = 0,
count = 0,
min,
expectedR,
expectedC;
/**
* this array holds the marked cells in the graph
*/
int markedCell[V][V] = {{0}};
/**
* this array holds the marked vertices
* 0 = unmarked
* 1 = marked
*/
int markedVertex[V] = {0};
markedVertex[0] = 1;
/**
* find MST
*/
while(!solved) {
min = INF;
count = 0;
expectedR = -1;
expectedC = -1;
/**
* find minimum weight from marked vertex
*
* note!
* graph[][] is a square matrix
* diagonal elements of the graph[][] are zeros
* and elements on either sides are same
* example: element graph[1][0] is same as graph[0][1]
* so, we will check only one side of the diagonal
*/
for (r = 0; r < V; r++) {
if (markedVertex[r] == 1) {
for (c = r; c < V; c++) {
if (graph[r][c] != 0 && graph[r][c] < min && !markedCell[r][c]) {
min = graph[r][c];
expectedR = r;
expectedC = c;
}
}
}
}
/**
* mark the newly found vertex for MST
*/
if (expectedR != -1 && expectedC != -1) {
markedCell[expectedR][expectedC] = 1;
markedCell[expectedC][expectedR] = 1;
markedVertex[expectedR] = 1;
markedVertex[expectedC] = 1;
}
/**
* check if the graph is solved
*/
for (i = 0; i < V; i++) {
if (markedVertex[i]) {
count++;
}
}
if (count == V) {
solved = 1;
}
}
displayMST(graph, markedCell);
}
/**
* this is the main function
*/
int main(void) {
/**
* 2d array which holds the weight of the edges
*
* note!
* graph[][] is a square matrix
* diagonal elements of the graph[][] are zeros
* and elements on either sides are same
* example: element graph[1][0] is same as graph[0][1]
*/
int graph[V][V] = {
{0, 5, 10, INF},
{5, 0, 4, 11},
{10, 4, 0, 5},
{INF, 11, 5, 0}
};
/**
* find MST using prim
*/
prim(graph);
return 0;
}