Javadoc for Task.par(Iterable<...>) should document on the result order.

[mchen07]

No description provided.

[junchuanwang]

Hi @mchen07 Min, I am not sure if I have enough context.

  /**
   * Creates a new task that will run each of the supplied tasks in parallel (e.g.
   * tasks[0] can be run at the same time as tasks[1]).
   * <p>
   * When all tasks complete successfully, you can use
   * {@link com.linkedin.parseq.ParTask#get()} to get a list of the results. If
   * at least one task failed, then this task will also be marked as failed. Use
   * {@link com.linkedin.parseq.ParTask#getTasks()} or
   * {@link com.linkedin.parseq.ParTask#getSuccessful()} to get results in this
   * case.
   * <p>
   * If the Iterable of tasks is empty, {@link com.linkedin.parseq.ParTask#get()}
   * will return an empty list.
   * <p>
   * Note that resulting task does not fast-fail e.g. if one of the tasks fail others
   * are not cancelled. This is different behavior than {@link Task#par(Task, Task)} where
   * resulting task fast-fails.
   *
   * @param tasks the tasks to run in parallel
   * @return The results of the tasks
   */
  public static <T> ParTask<T> par(final Iterable<? extends Task<? extends T>> tasks) {
    return tasks.iterator().hasNext()
        ? new ParTaskImpl<T>("par", tasks)
        : new ParTaskImpl<T>("par");
  }

When all tasks complete successfully, you can use
   * {@link com.linkedin.parseq.ParTask#get()} to get a list of the results.

Seems pretty clear to me?