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Answered by
wlandau
Nov 13, 2022
Replies: 1 comment 1 reply
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This is an instance of #94 (comment). You could try substituting expressions instead of the actual data values. values <- tibble(
...,
date_fun = purrr::map(c("2022-11-04","2022-11-11"), ~rlang::call2("as.Date", .x))
)
There are several workarounds in R that may allow you to relax this requirement: for example, a wrapper around |
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1 reply
Answer selected by
decat7
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This is an instance of #94 (comment). You could try substituting expressions instead of the actual data values.
There are several workarounds in R that may allow you to relax this requirement: for example, a wrapper around
make_dataset()
that converts a supplied character string to a date before callingmake_dataset()
.